我是 PHP的新手,正在寻找从数据库返回数据的有效方法.假设我有一个UserProfile表,它与UserInterest和UserContact有一对多的关系：

Select p.Id,p.FirstName,p.LastName,i.Name as Interests,c.Email,c.Phone
from UserProfile p
left join UserInterest i on p.Id = i.UserProfileId
left join UserContact c on p.Id = c.UserProfileId
where p.Id = 1

检索数据的有效方法是创建多维数组,例如：

$user = array(  "FirstName" => "John","LastName" => "Doe","Gender" => "Male","Interests" => array(
                    "Hiking","Cooking"),"Contact" => array(
                    "Email" => "john.doe@gmail.com","Phone" => "(555) 555-5555"));

我似乎无法理解如何在PHP中构建它.对于像兴趣这样的简单数据,我可以在查询中使用group_concat(i.Name)作为Interests将兴趣作为逗号分隔的列表返回到单行中,但是,对于像Contact这样的关联数组,我希望能够使用$user [‘Contact’] [‘Email’]获取数组中每个键的句柄.

从“最佳实践”的角度来看,我认为在一个查询中构建这样的数组要比多次访问数据库以检索这些数据要好得多.

谢谢！

尼尔

for each row
     $user["FirstName"] = row->FirstName;
     $user["LastName"] = row->LastName;
     $user["Interests"][] = row->Interests;
     $user["Contact"]["Email"] = row->Email;
     $user["Contact"]["Phone"] = row->Phone;
next