脚本宝典收集整理的这篇文章主要介绍了实验三，脚本宝典觉得挺不错的，现在分享给大家，也给大家做个参考。

task1

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <windows.h>
#define N 80

void printText(int line, int col, char text[]);
void printSpaces(int n);
void printBlankLines(int n);

int main()
{
	int line, col, i;
	char text[N] = "hi, May~";

	srand(time(0));

	for (i = 1; i <= 10; ++i)
	{
		line = rand() % 25;
		col = rand() % 80;
		printText(line, col, text);
		Sleep(1000);
	}

	return 0;
}

void printSpaces(int n)
{
	int i;

	for (i = 1; i <= n; ++i)
		printf(" ");
}

void printBlankLines(int n)
{
	int i;

	for (i = 1; i <= n; ++i)
		printf("n");
}

void printText(int line, int col, char text[])
{
	printBlankLines(line - 1);
	printSpaces(col - 1);
	printf("%s", text);
}

功能：在屏幕上随机打印十个“hi，May~”

task2_1

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
long long fac(int n); 
int main()
{
	int i, n;
	printf("Enter n: ");
	scanf("%d", &n);
	for (i=1; i<=n; ++i)
		printf("%d! = %lldn", i, fac(i));
	return 0;
}
long long fac(int n)
{
	static long long p=1;
	
	p=p * n;
	return p;
}
插入printf("p = %lldn", p);在“staticlonglongp=1;”后的截图

task2_2

#include <stdio.h>
int func(int, int);
int main()
{
    int k = 4, m = 1, p1, p2;
    p1 = func(k, m);
    p2 = func(k, m);
    printf("%d,%dn", p1, p2);
    return 0;
}
int func(int a, int b)
{
    static int m = 0, i = 2;
    i += m + 1;
    m = i + a + b;
    return m;
}

问题回答： 1.实验运行结果与理论分析得到的结果一致； 2.局部static变量的特性： 在函数调用后其值依然保留，并可影响下次调用过程。

task3

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
long long fun(int n);
int main()
{
    int n;
    long long f;
    while (scanf("%d", &n) != EOF)
    {
        f = fun(n);
        printf("n = %d, f = %lldn", n, f);
    }
    return 0;
}

long long fun(int n)
{
    int i;
    long long a = 0, p = 1;
    if (n == 0) a = 1;
    else
    {
        for (i = 1;i <= n;i++)
        {
            p = p * 2;
        }
        a = p - 1;
    }
    return a;
}

task4

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<stdlib.h>
int i;
void hanoi(unsigned n, char from, char to, char temp);
void move(unsigned n, char from, char to);
int main()
{
    unsigned n;
    while (scanf("%u", &n) != EOF)
    {
        i = 0;
        hanoi(n, 'A', 'C', 'B');
        printf("一共移动了%d次", i);
    }

    system("pause");
}
void hanoi(unsigned n, char from, char to, char temp)
{
    if (n == 1)
        move(n, from, to);
    else
    {
        hanoi(n - 1, from, temp, to);
        move(n, from, to);
        hanoi(n - 1, temp, to, from);
    }
}
void move(unsigned n, char from, char to)
{
    i++;
    printf("第%u个盘子: %c-->%cn", n, from, to);
}

task5

#include<stdio.h>
#include<stdlib.h>
#include<math.h>
int is_prime(int n);
int main()
{
    int n, p, q, flagp, flagq;
    for (n = 4;n <= 20;n += 2)
    {
        p = 1;
        do
        {
            p++;
            q = n - p;
            flagp = is_prime(p);
            flagq = is_prime(q);
        } while (flagq * flagp == 0);
    printf("%d =%d + %dn", n, p, q);
}
return 0;
}
int is_prime(int n)
{
    int k;
    for (k = 2;k <= sqrt(n);k++)
        if (n % k == 0)
        {
            return 0;
        }
    return 1;

}

task6

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<stdlib.h>
long fun(long s);
int main()
{
long s, t;
printf("Enter a number:");
while (scanf("%ld", &s) != EOF)
{
	t = fun(s);
	printf("new number is:%ldnn", t);
	printf("Enter a number:");
	}
	
	system("pause");
}
long fun(long s)
{
	long i, p, t = 0, x = 0, m;
	p = s;
	while (p != 0)
	{
	    i = p % 10;
	    if (i % 2 == 1)
		t = t * 10 + i;
	    p /= 10;
	}
	while (t != 0)
	{
    	    m = t % 10;
    	    x = x * 10 + m;
    	    t /= 10;
	}

	return x;
}

实验总结： 部分函数运用不太熟练，还需要进一步加强练习。

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