脚本宝典收集整理的这篇文章主要介绍了台球摆放问题，脚本宝典觉得挺不错的，现在分享给大家，也给大家做个参考。
如何摆放，大号小号最分散
>>> links = [[0, 1], [0, 2], [1, 2], [1, 3], [2, 4], [3, 5], [3, 6], [4, 7], [4, 8], [5, 6], [6, 7], [7, 8], [5, 9], [5, 10], [6, 10], [6, 11], [7, 11], [7, 12], [8, 12], [8, 13], [9, 10], [10, 11], [11, 12], [12, 13]]
>>> def score(s=[]): return sum([(c[0] in s) ^ (c[1] in s) for c in links])...>>> rs = []>>> for c in itertools.combinations(range(14), 7): rs.append([c, score(c)])...>>> rs[0:10][[(0, 1, 2, 3, 4, 5, 6), 7], [(0, 1, 2, 3, 4, 5, 7), 9], [(0, 1, 2, 3, 4, 5, 8), 8], [(0, 1, 2, 3, 4, 5, 9), 6], [(0, 1, 2, 3, 4, 5, 10), 8], [(0, 1, 2, 3, 4, 5, 11), 10], [(0, 1, 2, 3, 4, 5, 12), 10], [(0, 1, 2, 3, 4, 5, 13), 8], [(0, 1, 2, 3, 4, 6, 7), 8], [(0, 1, 2, 3, 4, 6, 8), 9]]>>> rs_df = pd.DataFrame(rs, columns=['c', 's'])>>> rs_df.head() c s0 (0, 1, 2, 3, 4, 5, 6) 71 (0, 1, 2, 3, 4, 5, 7) 92 (0, 1, 2, 3, 4, 5, 8) 83 (0, 1, 2, 3, 4, 5, 9) 64 (0, 1, 2, 3, 4, 5, 10) 8>>> rs_df.shape(3432, 2)>>> 39*16624>>> 39*16*116864>>> rs_df['s'].value_counts()14 60213 58412 52215 50811 37216 27210 2189 13617 1048 667 246 165 8Name: s, dtype: int64
st = rs_df.groupby('s')['c'].size().reset_index()
>>> st['r'] = st['c'] / st['c'].sum()>>> st['rc'] = st['r'].cumsum()>>> st s c r rc0 5 8 0.002331 0.0023311 6 16 0.004662 0.0069932 7 24 0.006993 0.0139863 8 66 0.019231 0.0332174 9 136 0.039627 0.0728445 10 218 0.063520 0.1363646 11 372 0.108392 0.2447557 12 522 0.152098 0.3968538 13 584 0.170163 0.5670169 14 602 0.175408 0.74242410 15 508 0.148019 0.89044311 16 272 0.079254 0.96969712 17 104 0.030303 1.000000
>>> best_c = rs_df[rs_df['s'].eq(17)&rs_df['c'].apply(lambda x: x[0]==0)]
>>> best_c['c'].apply(lambda x: [1 in x, 2 in x]).value_counts()[False, True] 18[True, False] 18[False, False] 16Name: c, dtype: int64
>>> best_c[best_c['c'].apply(lambda x: (1 in x) & (2 not in x))] c s548 (0, 1, 4, 5, 6, 8, 11) 17549 (0, 1, 4, 5, 6, 8, 12) 17553 (0, 1, 4, 5, 6, 9, 12) 17556 (0, 1, 4, 5, 6, 10, 12) 17558 (0, 1, 4, 5, 6, 11, 12) 17559 (0, 1, 4, 5, 6, 11, 13) 17560 (0, 1, 4, 5, 6, 12, 13) 17571 (0, 1, 4, 5, 7, 10, 12) 17572 (0, 1, 4, 5, 7, 10, 13) 17574 (0, 1, 4, 5, 7, 11, 13) 17612 (0, 1, 4, 6, 8, 9, 11) 17613 (0, 1, 4, 6, 8, 9, 12) 17616 (0, 1, 4, 6, 8, 10, 12) 17622 (0, 1, 4, 6, 9, 10, 12) 17624 (0, 1, 4, 6, 9, 11, 12) 17625 (0, 1, 4, 6, 9, 11, 13) 17626 (0, 1, 4, 6, 9, 12, 13) 17629 (0, 1, 4, 6, 10, 12, 13) 17>>> best_c[best_c['c'].apply(lambda x: (1 not in x) & (2 not in x))] c s1285 (0, 3, 4, 5, 7, 10, 12) 171286 (0, 3, 4, 5, 7, 10, 13) 171288 (0, 3, 4, 5, 7, 11, 13) 171326 (0, 3, 4, 6, 8, 9, 11) 171327 (0, 3, 4, 6, 8, 9, 12) 171330 (0, 3, 4, 6, 8, 10, 12) 171336 (0, 3, 4, 6, 9, 10, 12) 171338 (0, 3, 4, 6, 9, 11, 12) 171339 (0, 3, 4, 6, 9, 11, 13) 171340 (0, 3, 4, 6, 9, 12, 13) 171343 (0, 3, 4, 6, 10, 12, 13) 171356 (0, 3, 4, 7, 9, 10, 12) 171357 (0, 3, 4, 7, 9, 10, 13) 171359 (0, 3, 4, 7, 9, 11, 13) 171362 (0, 3, 4, 7, 10, 11, 13) 171363 (0, 3, 4, 7, 10, 12, 13) 17
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