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(1)task1.asm源码:
assume cs:code, ds:data data segment x dw 1020h, 2240h, 9522h, 5060h, 3359h, 6652h, 2530h, 7031h y dw 3210h, 5510h, 6066h, 5121h, 8801h, 6210h, 7119h, 3912h data ends code segment start: mov ax, data mov ds, ax mov si, offset x mov di, offset y call add128 mov ah, 4ch int 21h add128: push ax push cx push si push di sub ax, ax mov cx, 8 s: mov ax, [si] adc ax, [di] mov [si], ax inc si inc si inc di inc di loop s pop di pop si pop cx pop ax ret code ends end start
inc指令,对ZF有影响,对CF没有影响:
(2)line31~line34的4条inc指令,能否替换成如下代码?你的结论的依据/理由是什么?
答:不能替换。因为inc指令不会改变标志寄存器CF的值,而add指令会改变。改变后对adc ax, [di] 有影响。
(3)在debug中调试,观察数据段中做128位加之前和加之后,数据段的值的变化。给出调试观察截
(1)程序task2.asm源码:
assume cs:code, ds:data data segment str db 80 dup(?) data ends code segment start: mov ax, data mov ds, ax mov si, 0 s1: mov ah, 1 int 21h mov [si], al cmp al, '#' je next inc si jmp s1 next: mov ah, 2 mov dl, 0ah int 21h mov cx, si mov si, 0 s2: mov ah, 2 mov dl, [si] int 21h inc si loop s2 mov ah, 4ch int 21h code ends end start
(2)运行测试截图:
(3)回答问题:
(1)task3.asm源码:
assume cs:code, ds:data data segment x dw 91, 792, 8536, 65521, 2021 len equ $- x data ends code segment start: mov ax, data mov ds, ax mov si, offset x mov cx, len / 2 s: mov ax,[si] call PRintNumber call printSpace inc si inc si loop s mov ax,4c00h int 21h printNumber: push cx mov cx, 0 mov bx, 10 s0: inc cx mov dx, 0 div bx push dx cmp ax, 0 je s1 jmp s0 s1: pop dx or dx,30H mov ah, 2 int 21h loop s1 pop cx ret printSpace: mov ah, 2 mov dl, ' ' int 21h ret code ends end start
(2)运行测试截图:
(1)task4.asm源码:
assume cs:code, ds:data data segment str db "asSEMbly language, IT's not difficult but tedious" len equ $ - str data ends code segment start: mov ax,data mov ds,ax mov si,offset str mov cx,len call strupr mov ax,4c00h int 21h strupr: s: mov al,[si] cmp al,97 jl s1 cmp al,122 jg s1 and al,11011111B mov [si],al s1: inc si loop s ret code ends end start
(2)在debug中调试截图( call strupr 调用之前,数据段的值,以及,调用之后,数据段的值)
assume cs:code, ds:data data segment str1 db "yes", '$' str2 db "no", '$' data ends code segment start: mov ax, data mov ds, ax mov ah, 1 int 21h mov ah, 2 mov bh, 0 mov dh, 24 mov dl, 70 int 10h cmp al, '7' je s1 mov ah, 9 mov dx, offset str2 int 21h jmp over s1: mov ah, 9 mov dx, offset str1 int 21h over: mov ah, 4ch int 21h code ends end start
assume cs:code code segment start: ; 42 interrupt routine install code mov ax, cs mov ds, ax mov si, offset int42 ; set ds:si mov ax, 0 mov es, ax mov di, 200h ; set es:di mov cx, offset int42_end - offset int42 cld rep movsb ; set IVT(Interrupt Vector Table) mov ax, 0 mov es, ax mov word ptr es:[42*4], 200h mov word ptr es:[42*4+2], 0 mov ah, 4ch int 21h int42: jmp short int42_start str db "welcome to 2049!" len equ $ - str ; display string "welcome to 2049!" int42_start: mov ax, cs mov ds, ax mov si, 202h mov ax, 0b800h mov es, ax mov di, 24*160 + 32*2 mov cx, len s: mov al, [si] mov es:[di], al mov byte ptr es:[di+1], 2 inc si add di, 2 loop s iret int42_end: nop code ends end start
assume cs:code code segment start: int 42 mov ah, 4ch int 21h code ends end start
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